Achievable logo
Achievable blue logo on white background

AP Calculus AB
review & study guide

Every unit of the course summarized, with each chapter linked to its lesson.
Achievable blue logo on white background
Achievable blue logo on white background
Reach your target score
Try Achievable AP Calculus AB
No credit card required
Achievable blue logo on white background
This free AP Calculus AB review summarizes all 8 units of Achievable's AP Calculus AB course: what each covers, the points to remember, and its 54 chapters in order. Read a unit before its test, or work through the whole guide before exam day.
Each chapter links to its full lesson in Achievable, with the review quizzes and full-length practice exams.
Achievable blue logo on white background

Unit 1: Limits

9 chapters
  • Limit trend: A limit describes what value a function approaches as xx approaches a number, not necessarily what its value is at that point.
  • Existence condition: A limit exists only if both one-sided limits exist and match, and f(a)f(a) does not need to be defined for the limit to exist.
  • Analytical methods: Always try direct substitution first, then use limit laws and composite function steps, with continuity at x=Lx=L required for lim⁡x→af(g(x))=f(L)\lim_{x \to a} f(g(x)) = f(L).
  • Algebraic techniques: Indeterminate forms like 00\frac{0}{0} require factoring, rationalizing, common denominators, or piecewise absolute value analysis before final substitution.
  • Infinity and continuity: Infinite limits create vertical asymptotes, limits at infinity describe horizontal asymptotes, special limits and the squeeze theorem apply, and continuity requires all three conditions.
Start this unit free
Achievable blue logo on white background

Unit 2: Derivative basics

7 chapters
  • Average and instantaneous rates: Average rate of change uses f(b)−f(a)b−a\frac{f(b)-f(a)}{b-a}, while instantaneous rate of change is found by f′(a)=lim⁡x→af(x)−f(a)x−af'(a) = \lim_{x \to a} \frac{f(x)-f(a)}{x-a} or f′(x)=lim⁡h→0f(x+h)−f(x)hf'(x) = \lim_{h \to 0} \frac{f(x+h)-f(x)}{h}.
  • AP recognition tricks: Identify which limit definition applies from x→ax \to a or h→0h \to 0, and use table values directly for average rate of change over [a,b][a,b].
  • Tangent and normal lines: A secant line represents the average rate of change, a tangent line represents the instantaneous rate of change, and y−f(a)=f′(a)(x−a)y - f(a) = f'(a)(x - a).
  • Basic derivative rules: The power rule, constant multiple rule, and sum/difference rule apply to xnx^n, c⋅f(x)c \cdot f(x), and f(x)=g(x)±h(x)f(x) = g(x) \pm h(x), and quotient and product rules handle products and quotients.
  • Special and validity rules: ddx(ex)=ex\frac{d}{dx} (e^x) = e^x, ddx(ln⁡x)=1x\frac{d}{dx} (\ln x) = \frac{1}{x}, differentiability implies continuity, and a discontinuity, sharp corner, cusp, or vertical tangent will not be differentiable there.
Study this unit in Achievable
Achievable blue logo on white background

Unit 3: Advanced differentiation

6 chapters
  • Chain rule basics: Differentiate composite functions f(g(x))f(g(x)) by multiplying the derivative of the outer function by the derivative of the inner function.
  • Common rule combinations: Identify overall structure first, then use (fg)′=f′g+fg′(fg)' = f'g + fg' or (fg)′=f′g−fg′g2\left(\frac{f}{g}\right)' = \frac{f'g - fg'}{g^2} with the chain rule for composite factors.
  • Implicit and higher derivatives: When yy is not explicitly defined as a function of xx, differentiate both sides with respect to xx, solve for dydx\frac{dy}{dx}, and differentiate again for d2ydx2\dfrac{d^2y}{dx^2}.
  • Log and inverse rules: Logarithmic differentiation streamlines complex products, quotients, and variable exponents, and the slope of f−1(x)f^{-1}(x) at (a,b)(a, b) is the reciprocal of the slope of f(x)f(x) at (b,a)(b, a).
Study this unit in Achievable
Achievable blue logo on white background

Unit 4: Contextual uses

6 chapters
  • Derivative meaning: The sign of f′(x)f'(x) indicates direction: positive = increasing, negative = decreasing, zero = not changing, and AP FRQ interpretations need input value, noun/subject, direction, and numerical value with units.
  • Motion interpretation: Positive means right and negative means left, while position graphs give velocity from slope and velocity graphs give acceleration from slope, so speeding up or slowing down comes from comparing velocity and acceleration signs.
  • Related rates strategy: Define variables, relate them with equations, differentiate with respect to time, then substitute known values after differentiating and solve for the unknown rate.
  • Approximations and limits: L(x)=f(a)+f′(a)(x−a)L(x) = f(a) + f'(a)(x - a) estimates nearby values, f′′(x)>0f''(x) > 0 gives an underestimate and f′′(x)<0f''(x) < 0 gives an overestimate, and L'Hopital's rule applies only to 00\dfrac{0}{0} or ±∞∞\pm \dfrac{\infty}{\infty}.
Study this unit in Achievable
Achievable blue logo on white background
Achievable blue logo on white background
Achievable AP Calculus AB
Pass the AP Calculus AB exam on your first try with Achievable's interactive online exam preparation course. Includes everything you need: easy-to-understand online textbook, 380+ review questions, and 3+ full-length practice exams.
Easy-to-understand online textbook
380+ chapter quizzes
3+ practice exams
Screenshot of the Achievable AP Calculus AB course dashboard
Achievable blue logo on white background

Unit 5: Analytical uses

7 chapters
  • Mean value theorem: If f(x)f(x) is continuous on [a,b][a,b] and differentiable on (a,b)(a,b), then ∃ c∈(a,b)\exists\, c \in (a,b) such that f′(c)=f(b)−f(a)b−af'(c) = \dfrac{f(b)-f(a)}{b-a}.
  • Rolle and EVT: Rolle's theorem is the special case f(a)=f(b)f(a)=f(b) and guarantees ∃ c∈(a,b)\exists\, c \in (a,b) such that f′(c)=0f'(c)=0, while EVT says a continuous function on [a,b][a,b] attains absolute maximum and minimum there.
  • First derivative test: Find critical points by setting f′(x)=0f'(x)=0 or where f′(x)f'(x) is undefined, then use the sign of f′(x)f'(x) to decide whether a critical point is a relative maximum or minimum.
  • Second derivative test: For extrema, the test applies only when f(c)f(c) is defined, f′(c)=0f'(c)=0, and f′′(c)≠0f''(c)\neq 0, and inflection points occur where f′′(x)f''(x) changes sign.
  • Graphs and optimization: f′(x)f'(x) gives slope and increasing or decreasing behavior, f′′(x)f''(x) gives concavity, curve sketching combines domain, intercepts, asymptotes, critical points, and inflection points, and optimization uses objective and constraint equations to find max or min values.
Study this unit in Achievable
Achievable blue logo on white background

Unit 6: Integration

9 chapters
  • Accumulated change: Accumulated change equals area under a rate function graph, with units as (vertical units) × (horizontal units), and it works for both constant and variable rates.
  • Signed area rules: Area above xx-axis is positive, area below xx-axis is negative, and net change (displacement) is the sum of signed areas.
  • Riemann sums: Approximate area under a curve by summing areas of rectangles or trapezoids after dividing [a,b][a, b] into nn subintervals of width Δx=b−an\Delta x = \frac{b-a}{n}.
  • Definite integrals: ∫abf(x)dx=lim⁡n→∞∑k=1nΔx⋅f(xk)\int_a^b f(x) dx = \lim_{n \to \infty} \sum_{k=1}^{n} \Delta x \cdot f(x_k), and it equals the exact net signed area under f(x)f(x) from aa to bb.
  • Accumulation functions: A(x)=∫axf(t)dtA(x) = \int_a^x f(t) dt, F′(x)=f(x)F'(x) = f(x), and h′(x)=f(g(x))⋅g′(x)h'(x) = f(g(x)) \cdot g'(x) for ∫ag(x)f(t)dt\int_a^{g(x)} f(t) dt.
Study this unit in Achievable
Achievable blue logo on white background

Unit 7: Differential equations

4 chapters
  • Differential equations: A differential equation relates an unknown function to one or more of its derivatives, and a solution satisfies the equation when substituted in.
  • Slope fields: Slope fields show solution behavior for differential equations by plotting the slope at each point (x,y)(x, y) with the specified slope.
  • Separation method: For first-order differential equations of the form dydx=f(x)g(y)\frac{dy}{dx} = f(x)g(y), isolate yy-terms with dydy and xx-terms with dxdx, then integrate both sides.
  • Exponential models: Exponential differential equations are modeled by dydt=ky\frac{dy}{dt} = ky, with general solution y=Cekty = Ce^{kt} and k>0k>0 for growth, k<0k<0 for decay.
Study this unit in Achievable
Achievable blue logo on white background

Unit 8: Applications of integrals

6 chapters
  • Average value: favg=1b−a∫abf(x) dxf_\text{avg} = \frac{1}{b-a} \int_a^b f(x) \, dx, and its units always match units of f(x)f(x), so check units to choose between average value and average rate of change.
  • Motion integrals: Displacement is ∫abv(t)dt\int_a^b v(t)dt, total distance is ∫ab∣v(t)∣dt\int_a^b |v(t)|dt, and position satisfies s(t)=s(a)+∫atv(x)dxs(t) = s(a) + \int_a^t v(x)dx.
  • Area between curves: Area is the definite integral of top minus bottom for vertical slices or right minus left for horizontal slices, and split the integral at intersection points when roles switch.
  • Volume solids: Use cross sections, the disk method V=π∫ab[R(x)]2 dxV = \pi \int_a^b [R(x)]^2 \, dx or V=π∫cd[R(y)]2 dyV = \pi \int_c^d [R(y)]^2 \, dy, and the washer method V=π∫ab[R(x)2−r(x)2]dxV = \pi \int_a^b [R(x)^2 - r(x)^2]dx.
Study this unit in Achievable
Achievable blue logo on white background

AP Calculus AB exam at a glance

Questions
42 multiple-choice questions, 6 free-response questions
Time
3 hours 10 minutes
Passing score
3 (on scale of 1-5)
Exam fee
$99
Achievable blue logo on white background

More on the AP Calculus AB exam

Achievable AP Calculus AB dashboard
Ace the AP Calculus AB. Guaranteed.
Achievable is the best AP Calculus AB exam prep course: effective, personalized, and convenient. With Achievable, you'll spend less time studying and hit your target score with confidence.